How to get rid of floating-point constants

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ssmith
ssmith 2021 年 11 月 16 日
コメント済み: James Tursa 2021 年 11 月 16 日
I am trying to evaluate this expression but I get an error saying I have a floating-point constant. If I add another parenthases to separate the 7 and e, then I get an error saying I am missing more parenthases when I know I am not. Any one have advice on how to fix this equation?
A = 25 - (100 - 7exp(5+cos(pi/3)))

回答 (1 件)

Dave B
Dave B 2021 年 11 月 16 日
The error you describe isn't what I'd expect, but you're certainly missing a *. Unless exp isn't the matlab function exp and is some e.g. symbolic variable?
A = 25 - (100 - 7*exp(5+cos(pi/3)))
A = 1.6378e+03
  2 件のコメント
ssmith
ssmith 2021 年 11 月 16 日
@Dave B Do you know what the error means "Invalid Floating-point constant"
James Tursa
James Tursa 2021 年 11 月 16 日
@ssmith The parser sees the characters 7e... and thinks you are trying to enter a floating point number like 7e2, but when it gets to the x character it can't read the exponent so it throws the error. Basically you have invalid syntax which was misleading the parser.

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