How to create a block diagonal matrix from the slices of a 3D matrix
4 ビュー (過去 30 日間)
古いコメントを表示
I have a large 3D matrix (K) composed of 200 slices , and I want to create a block diagonal matrix from the slices of it without looping. For example
K(:,:,1) =[1 2;3 4]
K(:,:,2) =[5 6;7 8]
K(:,:,3) =[9 10;11 12]
.
.
.
K(:,:,200) =[1 10;13 15]
if we assume the number of slice is 3, the output should be
1 2 0 0 0 0
3 4 0 0 0 0
0 0 5 6 0 0
0 0 7 8 0 0
0 0 0 0 9 10
0 0 0 0 11 12
But how the block diagonal matrix created from all the 200 slices without looping?
0 件のコメント
採用された回答
Azzi Abdelmalek
2014 年 10 月 2 日
k(:,:,1) =[1 2;3 4]
k(:,:,2) =[5 6;7 8]
k(:,:,3) =[9 10;11 12]
q=num2cell(k,[1,2])
blkdiag(q{:})
4 件のコメント
Matt J
2014 年 10 月 2 日
Note that this still uses a for-loop inside num2cell.m, though how much that hurts you, I don't know.
Note also that my 2nd answer here was the same as this, except that it returns the result in sparse form, which is normally more desirable for block diagonal matrices with small blocks.
その他の回答 (3 件)
Azzi Abdelmalek
2014 年 10 月 2 日
k(:,:,1) =[1 2;3 4]
k(:,:,2) =[5 6;7 8]
k(:,:,3) =[9 10;11 12]
out=[];
for ii=1:size(k,3)
out=blkdiag(out,k(:,:,ii))
end
参考
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!