for loop for matlab files
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Evan
2014 年 9 月 2 日
編集済み: Evan
2014 年 9 月 2 日
% where N is the number of files
for i = 1:N
load(['M' num2str(N) '.m'])
end
This will change based on whether or not you know how many of these files exist (if not, look into using the dir command) and how you want them to be stored (if they're all identically named variables but differ in size, I would suggest a structure; if they're the same size, you could just use a higher-dimension matrix).
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その他の回答 (1 件)
Iain
2014 年 9 月 2 日
Ugh. The curse of eval strikes again.
That'll run them in a loop, but god help anyone trying to debug it.
for i = 1:m
eval(['M' num2str(i)])
end
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