Showing me wrong Matrix Size.

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Amit Chakraborty
Amit Chakraborty 2021 年 9 月 23 日
コメント済み: Walter Roberson 2021 年 9 月 23 日
fds = fileDatastore(" " );
N= cell2mat(fds.Files);
kk= ones(64,1);
OO= N.*kk;
  • I have created a Data store with a matlab data. The original size of the data was : 2031616x64.
  • In the second line of the code I just convert the file from the cell type
  • Created the ones matrix
  • when i am trying to multiply , the reultant varibale "OO" is having the wrong size: 64x161. But if I have done it in a normal way (without creating Datastore) it's size would have been : 2031616x1 which is basically correct and I need.
My question is that , what mistake I am making here? I am newly working with the "Datastore" stuffs in MATLAB.
Thanks in Advance.

採用された回答

Walter Roberson
Walter Roberson 2021 年 9 月 23 日
N= cell2mat(fds.Files);
The Files field of a FileDataStore is a cell array of character vectors that holds file names. When you cell2mat() that, you get a character vector or character array. Character vectors and character arrays are treated as numeric when you do numeric operations -- for example,
'A' + 1
looks up the Unicode code position for the letter 'A' (which is 65), and adds 1 to that code (getting 66 -- which happens to be the code position for the letter 'B')
Thus, you are doing mathematics on the characters of file names, not on the contents of the files.
  2 件のコメント
Walter Roberson
Walter Roberson 2021 年 9 月 23 日
You might possibly be able to use a transform store; https://www.mathworks.com/help/matlab/ref/matlab.io.datastore.transform.html
Transform stores do not perform the transformation until the data is needed by the program. But at some point, the multiplication needs to be done.
It looks to me as if in your case, you could just sum() the data along its second dimension instead of coding in terms of multiplying by a matrix.

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その他の回答 (1 件)

Fabio Freschi
Fabio Freschi 2021 年 9 月 23 日
multiply without the 'dot'
OO= N*kk;

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