comparing and addition of two matrices
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a=[9,41,48,0,0,0,0,0;15,47,56,0,0,0,0,0;25,67,0,0,0,0,0,0];b=[21;11;30]; I am having three rows in a and b. I need to compare a with b for example i am taking 21 from b and comparing with the first row of a, first row first column value is 9, but b value is 21 its greater than a so the remaining columns in first row should be added by 5 except zero [9, 46, 53,0,0,0,0,0]. Similarly in the second row of a has to be compared with second row of b [20,52,61,0,0,0,0,0]. Third row [25,72,0,0,0,0,0,0]. Finally my a=[9,46,53,0,0,0,0,0;20,52,61,0,0,0,0,0;25,72,0,0,0,0,0,0]. suggest with some points.
4 件のコメント
dpb
2014 年 6 月 10 日
That isn't quite the rule he gave, though--he adds for all columns from 2:end irrespective of the first column comparison; it's only that first column that is dependent on the value in b, apparently. (At least that's what his example gives as a result.)
Geoff Hayes
2014 年 6 月 10 日
Huh. I could have sworn the second row of b didn't have 5 added to the elements from 2:end. I see now how it does from 1:end though...
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dpb
2014 年 6 月 10 日
Look up "logical addressing"...
>> ix=[b<a(:,1) a(:,2:end)>0];
>> a(ix)=a(ix)+5
a =
9 46 53 0 0 0 0 0
20 52 61 0 0 0 0 0
25 72 0 0 0 0 0 0
2 件のコメント
dpb
2014 年 6 月 11 日
Chuckles...thanks, glad I did seemingly get the intent correct; wasn't really sure if the actual example really was what was intended or not.
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