Why does bwperim give wrong perimeter?

3 ビュー (過去 30 日間)
Steven
Steven 2014 年 4 月 15 日
回答済み: Walter Roberson 2014 年 4 月 15 日
I wanted to get the perimeter of the following circle. I used two methods, but got completely different results!
1. I used bwperim (after getting binary):
%% BW is the binary image of original greyscale image
BW_perim = bwperim(BW);
L = sum(sum(BW_perim));
I got this:
2. I used imfindcircle:
[centers,radius] = imfindcircles(greyscale);
L2 = 2*pi*radius
and I got this:
The results are completely different. The first one value is about 7 times the second one (in dimensional domain, the second one is reasonable).
I do not know why! Interesting is that the area is almost correct and the results are similar, but the perimeter is not!
1. What is wrong with the first method? Because my other images are not full circles and I have to use bwperim to get the perimeter.
Thanks so much!

採用された回答

Anand
Anand 2014 年 4 月 15 日
編集済み: Anand 2014 年 4 月 15 日
The circle you are trying to measure is not a perfect circle, so technically you can't use 2*pi*radius as the formula for perimeter. Moreover, even what bwperim returns is an approximation that is dependent on the connectivity used, the resolution of the image and how perimeters of small line segments in the binary image are computed.
I would continue using bwperim.
  1 件のコメント
Steven
Steven 2014 年 4 月 15 日
Thanks Anand. So which one is the closest to the true value?
How can I get almost the accurate perimeter?
Thanks!
Steven

サインインしてコメントする。

その他の回答 (1 件)

Walter Roberson
Walter Roberson 2014 年 4 月 15 日
Consider using imclose() on the labeled image and then taking the perimeter.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by