For the differential equation how would I create a Matlab function that takes no inputs and returns the following outputs: # Two vectors, x and y, containing the points where the differential equation has been approximated and the corresponding value of the solution. # A real number representing the integral of the approximated solution in the interval where the differential equation has been solved. For the ordinary differential equation: d3y dx3 + dydx - xy + d2ydx2 = 2; x 3 [1:1; 5:8] with initial conditions y(0) = 0:0616;dydx(0) = 0.5886; d2ydx2(0)=0.0989

how to create diferential equation with initial conditions ?

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Dave Martin 2014 年 4 月 3 日

コメント済み: RahulTandon 2015 年 7 月 8 日

For the differential equation how would I create a Matlab function that takes no inputs and returns the following outputs:

Two vectors, x and y, containing the points where the differential equation has been approximated and the corresponding value of the solution.
A real number representing the integral of the approximated solution in the interval where the differential equation has been solved.

For the ordinary differential equation:
d3y dx3 + dydx - xy + d2ydx2 = 2; 
x 3 [1:1; 5:8]

with initial conditions y(0) = 0:0616;dydx(0) = 0.5886; d2ydx2(0)=0.0989

Star Strider 2014 年 4 月 3 日

編集済み: Star Strider 2014 年 4 月 3 日

What does ‘x 3 [1:1; 5:8]’ mean?

RahulTandon 2015 年 7 月 8 日

x 3 [1:1, 5:8] means x3 = [1:1,5:8] Am i right?

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