finding index inside a region

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Mohammad Golam Kibria
Mohammad Golam Kibria 2011 年 7 月 26 日
コメント済み: Image Analyst 2021 年 4 月 23 日
suppose I have a matrix I.
I =
4 4 4 4 4 4 4
4 1 1 1 1 3 0
4 1 3 3 1 3 0
4 1 3 3 1 3 0
4 1 1 1 1 3 0
4 4 4 4 4 4 4
idx is the index of 1's in the matrix including all 3's inside 1;
I need to find the index of those 3s those are inside 1s.
I tried with the following code.Perhaps this is not the correct one.
idx1=find(I(idx)==3);
How can I get that? can any body help?
Thanks

採用された回答

Image Analyst
Image Analyst 2011 年 7 月 26 日
This will work to get ONLY the 3's inside, not any old number.
binaryImage = I==1
filledImage = imfill(binaryImage, 'holes')
maskedImage = I .* filledImage
justThe3s = ismember(maskedImage, 3)
[rows cols] = find(justThe3s)
You could use either the logical indexes "justThe3s" or the rows and cols variables, whichever you mean by "indexes."
  5 件のコメント
Nick Ward
Nick Ward 2021 年 4 月 23 日
Thanks for the reply.
I think this is what I'm looking for although I get these errors. Any ideas?
Image Analyst
Image Analyst 2021 年 4 月 23 日
@Nick Ward, attach your image/matrix, and m-file in a new question after reading this:

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その他の回答 (1 件)

Andrei Bobrov
Andrei Bobrov 2011 年 7 月 26 日
BW = I==1;
[~,L] = bwboundaries(BW);
idx = find(L==2)
  1 件のコメント
Image Analyst
Image Analyst 2011 年 7 月 26 日
This will get any collection of numbers inside a contiguous perimeter of 1's, not just the 3's. For example it would also find 4's, 42's, and 18's - whatever happened to be inside. Mohammad, see my answer if you want something that is more "tunable" to just one single number, if that is what you want.

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