how to create empty string arrays and then populate them through arrayName(indexNumber) syntax

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John
John 2014 年 2 月 20 日
回答済み: Nigel Nettheim 2023 年 6 月 9 日
The following works for numbers:
B=[];
B(1)=10;
but how to make it work for strings such as
C=[''];
C(1)='hello';% does NOT work

回答 (3 件)

Ronald Whiddon
Ronald Whiddon 2019 年 5 月 10 日
Declare an empty string array in this manner:
C=string.empty;
C(1)='hello';
C(2) = 'goodbye';

Dishant Arora
Dishant Arora 2014 年 2 月 20 日
c{1} = 'hello';
  2 件のコメント
Ronald Whiddon
Ronald Whiddon 2019 年 5 月 10 日
This is a workaround, but it actually creates a cell array of strings.
Stephen23
Stephen23 2019 年 5 月 10 日
編集済み: Stephen23 2019 年 5 月 10 日
"This is a workaround, but it actually creates a cell array of strings. "
At the time this question was posed (and answered) the string class did not exist (it was only introduced in R2016b). Each element of a character array stores only one character, so (until the string class was introduced) the only way to store multiple characters using a scalar index (as the question poses) is to use a cell array. From that persepctive it is not a "workaround", it is the correct solution for versions of MATLAB before R2016b.

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Nigel Nettheim
Nigel Nettheim 2023 年 6 月 9 日
You can initialise an empty string array with:
s = strings(0)
to which the response is:
s =
0×0 empty string array

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